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12(x+3)=(2x+9)+6
We move all terms to the left:
12(x+3)-((2x+9)+6)=0
We multiply parentheses
12x-((2x+9)+6)+36=0
We calculate terms in parentheses: -((2x+9)+6), so:We get rid of parentheses
(2x+9)+6
We get rid of parentheses
2x+9+6
We add all the numbers together, and all the variables
2x+15
Back to the equation:
-(2x+15)
12x-2x-15+36=0
We add all the numbers together, and all the variables
10x+21=0
We move all terms containing x to the left, all other terms to the right
10x=-21
x=-21/10
x=-2+1/10
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