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2/3x+1/2=5/2+x
We move all terms to the left:
2/3x+1/2-(5/2+x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-2
x!=-2/1
x!=-2
x∈R
2/3x-(+x+5/2)+1/2=0
We get rid of parentheses
2/3x-x-5/2+1/2=0
We calculate fractions
There is no solution for this equation
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