/4x+5=3x+4

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Solution for /4x+5=3x+4 equation:



/4x+5=3x+4
We move all terms to the left:
/4x+5-(3x+4)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We get rid of parentheses
/4x-3x-4+5=0
We multiply all the terms by the denominator
-3x*4x-4*4x+5*4x+=0
We add all the numbers together, and all the variables
-3x*4x-4*4x+5*4x=0
Wy multiply elements
-12x^2-16x+20x=0
We add all the numbers together, and all the variables
-12x^2+4x=0
a = -12; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-12)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-12}=\frac{-8}{-24} =1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-12}=\frac{0}{-24} =0 $

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