12(6x-2)-3=7(1-x)+3(x+1)

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Solution for 12(6x-2)-3=7(1-x)+3(x+1) equation: 



12(6x-2)-3=7(1-x)+3(x+1)

We move all terms to the left:

12(6x-2)-3-(7(1-x)+3(x+1))=0

We add all the numbers together, and all the variables

12(6x-2)-(7(-1x+1)+3(x+1))-3=0

We multiply parentheses

72x-(7(-1x+1)+3(x+1))-24-3=0



We calculate terms in parentheses: -(7(-1x+1)+3(x+1)), so:

7(-1x+1)+3(x+1)

We multiply parentheses

-7x+3x+7+3

We add all the numbers together, and all the variables

-4x+10

Back to the equation:

-(-4x+10)



We add all the numbers together, and all the variables

72x-(-4x+10)-27=0

We get rid of parentheses

72x+4x-10-27=0

We add all the numbers together, and all the variables

76x-37=0

We move all terms containing x to the left, all other terms to the right

76x=37

x=37/76

x=37/76

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