4(3/4n+1)=5-2(n-1/2)

Solution for 4(3/4n+1)=5-2(n-1/2) equation:

4(3/4n+1)=5-2(n-1/2)

We move all terms to the left:

4(3/4n+1)-(5-2(n-1/2))=0


Domain of the equation: 4n+1)!=0

n∈R


We add all the numbers together, and all the variables

4(3/4n+1)-(5-2(+n-1/2))=0

We multiply parentheses

12n-(5-2(+n-1/2))+4=0

We multiply all the terms by the denominator


12n*2))-(5-2(+n-1+4*2))=0

We add all the numbers together, and all the variables

12n*2))-(5-2(n+7))=0

We add all the numbers together, and all the variables

12n*2))-(5-2(n=0

Wy multiply elements

24n^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{48}=0$