4(5x-2)-3=7(2-x)+6(x+1)

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Solution for 4(5x-2)-3=7(2-x)+6(x+1) equation: 



4(5x-2)-3=7(2-x)+6(x+1)

We move all terms to the left:

4(5x-2)-3-(7(2-x)+6(x+1))=0

We add all the numbers together, and all the variables

4(5x-2)-(7(-1x+2)+6(x+1))-3=0

We multiply parentheses

20x-(7(-1x+2)+6(x+1))-8-3=0



We calculate terms in parentheses: -(7(-1x+2)+6(x+1)), so:

7(-1x+2)+6(x+1)

We multiply parentheses

-7x+6x+14+6

We add all the numbers together, and all the variables

-1x+20

Back to the equation:

-(-1x+20)



We add all the numbers together, and all the variables

20x-(-1x+20)-11=0

We get rid of parentheses

20x+1x-20-11=0

We add all the numbers together, and all the variables

21x-31=0

We move all terms containing x to the left, all other terms to the right

21x=31

x=31/21

x=1+10/21

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