12(2u-1)=10(1+u)+4+2

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Solution for 12(2u-1)=10(1+u)+4+2 equation: 



12(2u-1)=10(1+u)+4+2

We move all terms to the left:

12(2u-1)-(10(1+u)+4+2)=0

We add all the numbers together, and all the variables

12(2u-1)-(10(u+1)+4+2)=0

We multiply parentheses

24u-(10(u+1)+4+2)-12=0



We calculate terms in parentheses: -(10(u+1)+4+2), so:

10(u+1)+4+2

We add all the numbers together, and all the variables

10(u+1)+6

We multiply parentheses

10u+10+6

We add all the numbers together, and all the variables

10u+16

Back to the equation:

-(10u+16)



We get rid of parentheses

24u-10u-16-12=0

We add all the numbers together, and all the variables

14u-28=0

We move all terms containing u to the left, all other terms to the right

14u=28

u=28/14

u=2

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