M+(m-2)+(3m)=68

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Solution for M+(m-2)+(3m)=68 equation:



+(M-2)+(3M)=68
We move all terms to the left:
+(M-2)+(3M)-(68)=0
We add all the numbers together, and all the variables
3M+(M-2)-68=0
We get rid of parentheses
3M+M-2-68=0
We add all the numbers together, and all the variables
4M-70=0
We move all terms containing M to the left, all other terms to the right
4M=70
M=70/4
M=17+1/2

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