120-40=(2)2x+8

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Solution for 120-40=(2)2x+8 equation: 



120-40=(2)2x+8

We move all terms to the left:

120-40-((2)2x+8)=0

We add all the numbers together, and all the variables

-(22x+8)+80=0

We get rid of parentheses

-22x-8+80=0

We add all the numbers together, and all the variables

-22x+72=0

We move all terms containing x to the left, all other terms to the right

-22x=-72

x=-72/-22

x=3+3/11

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