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11x+2/3x=37
We move all terms to the left:
11x+2/3x-(37)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
11x*3x-37*3x+2=0
Wy multiply elements
33x^2-111x+2=0
a = 33; b = -111; c = +2;
Δ = b2-4ac
Δ = -1112-4·33·2
Δ = 12057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-111)-\sqrt{12057}}{2*33}=\frac{111-\sqrt{12057}}{66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-111)+\sqrt{12057}}{2*33}=\frac{111+\sqrt{12057}}{66} $
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