8(2x+1)=10(x+5)

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Solution for 8(2x+1)=10(x+5) equation: 



8(2x+1)=10(x+5)

We move all terms to the left:

8(2x+1)-(10(x+5))=0

We multiply parentheses

16x-(10(x+5))+8=0



We calculate terms in parentheses: -(10(x+5)), so:

10(x+5)

We multiply parentheses

10x+50

Back to the equation:

-(10x+50)



We get rid of parentheses

16x-10x-50+8=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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