-3(3x-4)+12=78

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Solution for -3(3x-4)+12=78 equation: 



-3(3x-4)+12=78

We move all terms to the left:

-3(3x-4)+12-(78)=0

We add all the numbers together, and all the variables

-3(3x-4)-66=0

We multiply parentheses

-9x+12-66=0

We add all the numbers together, and all the variables

-9x-54=0

We move all terms containing x to the left, all other terms to the right

-9x=54

x=54/-9

x=-6

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