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11=s2
We move all terms to the left:
11-(s2)=0
We add all the numbers together, and all the variables
-1s^2+11=0
a = -1; b = 0; c = +11;
Δ = b2-4ac
Δ = 02-4·(-1)·11
Δ = 44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44}=\sqrt{4*11}=\sqrt{4}*\sqrt{11}=2\sqrt{11}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{11}}{2*-1}=\frac{0-2\sqrt{11}}{-2} =-\frac{2\sqrt{11}}{-2} =-\frac{\sqrt{11}}{-1} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{11}}{2*-1}=\frac{0+2\sqrt{11}}{-2} =\frac{2\sqrt{11}}{-2} =\frac{\sqrt{11}}{-1} $
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