-3(2c+4)=5(6-c)

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Solution for -3(2c+4)=5(6-c) equation: 



-3(2c+4)=5(6-c)

We move all terms to the left:

-3(2c+4)-(5(6-c))=0

We add all the numbers together, and all the variables

-3(2c+4)-(5(-1c+6))=0

We multiply parentheses

-6c-(5(-1c+6))-12=0



We calculate terms in parentheses: -(5(-1c+6)), so:

5(-1c+6)

We multiply parentheses

-5c+30

Back to the equation:

-(-5c+30)



We get rid of parentheses

-6c+5c-30-12=0

We add all the numbers together, and all the variables

-1c-42=0

We move all terms containing c to the left, all other terms to the right

-c=42

c=42/-1

c=-42

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