8+7/8x=6+1/5x

Solution for 8+7/8x=6+1/5x equation:

8+7/8x=6+1/5x

We move all terms to the left:

8+7/8x-(6+1/5x)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

7/8x-(1/5x+6)+8=0

We get rid of parentheses

7/8x-1/5x-6+8=0

We calculate fractions


35x/40x^2+(-8x)/40x^2-6+8=0

We add all the numbers together, and all the variables

35x/40x^2+(-8x)/40x^2+2=0

We multiply all the terms by the denominator


35x+(-8x)+2*40x^2=0

Wy multiply elements

80x^2+35x+(-8x)=0

We get rid of parentheses

80x^2+35x-8x=0

We add all the numbers together, and all the variables

80x^2+27x=0

a = 80; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·80·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*80}=\frac{-54}{160}
=-27/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*80}=\frac{0}{160}
=0
$