110=6(1+3a)-4

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Solution for 110=6(1+3a)-4 equation: 



110=6(1+3a)-4

We move all terms to the left:

110-(6(1+3a)-4)=0

We add all the numbers together, and all the variables

-(6(3a+1)-4)+110=0



We calculate terms in parentheses: -(6(3a+1)-4), so:

6(3a+1)-4

We multiply parentheses

18a+6-4

We add all the numbers together, and all the variables

18a+2

Back to the equation:

-(18a+2)



We get rid of parentheses

-18a-2+110=0

We add all the numbers together, and all the variables

-18a+108=0

We move all terms containing a to the left, all other terms to the right

-18a=-108

a=-108/-18

a=+6

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