13+n=4(1+n)

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Solution for 13+n=4(1+n) equation: 



13+n=4(1+n)

We move all terms to the left:

13+n-(4(1+n))=0

We add all the numbers together, and all the variables

n-(4(n+1))+13=0



We calculate terms in parentheses: -(4(n+1)), so:

4(n+1)

We multiply parentheses

4n+4

Back to the equation:

-(4n+4)



We get rid of parentheses

n-4n-4+13=0

We add all the numbers together, and all the variables

-3n+9=0

We move all terms containing n to the left, all other terms to the right

-3n=-9

n=-9/-3

n=+3

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