(2x-6)+(x+3)2=26

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Solution for (2x-6)+(x+3)2=26 equation: 



(2x-6)+(x+3)2=26

We move all terms to the left:

(2x-6)+(x+3)2-(26)=0

We multiply parentheses

(2x-6)+2x+6-26=0

We get rid of parentheses

2x+2x-6+6-26=0

We add all the numbers together, and all the variables

4x-26=0

We move all terms containing x to the left, all other terms to the right

4x=26

x=26/4

x=6+1/2

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