11(z+2)-3(z-2)=5(z-2)+2(z-1)

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Solution for 11(z+2)-3(z-2)=5(z-2)+2(z-1) equation: 



11(z+2)-3(z-2)=5(z-2)+2(z-1)

We move all terms to the left:

11(z+2)-3(z-2)-(5(z-2)+2(z-1))=0

We multiply parentheses

11z-3z-(5(z-2)+2(z-1))+22+6=0



We calculate terms in parentheses: -(5(z-2)+2(z-1)), so:

5(z-2)+2(z-1)

We multiply parentheses

5z+2z-10-2

We add all the numbers together, and all the variables

7z-12

Back to the equation:

-(7z-12)



We add all the numbers together, and all the variables

8z-(7z-12)+28=0

We get rid of parentheses

8z-7z+12+28=0

We add all the numbers together, and all the variables

z+40=0

We move all terms containing z to the left, all other terms to the right

z=-40

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