32x-8=(14x+4)(4x-8)

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Solution for 32x-8=(14x+4)(4x-8) equation:



32x-8=(14x+4)(4x-8)
We move all terms to the left:
32x-8-((14x+4)(4x-8))=0
We multiply parentheses ..
-((+56x^2-112x+16x-32))+32x-8=0
We calculate terms in parentheses: -((+56x^2-112x+16x-32)), so:
(+56x^2-112x+16x-32)
We get rid of parentheses
56x^2-112x+16x-32
We add all the numbers together, and all the variables
56x^2-96x-32
Back to the equation:
-(56x^2-96x-32)
We add all the numbers together, and all the variables
32x-(56x^2-96x-32)-8=0
We get rid of parentheses
-56x^2+32x+96x+32-8=0
We add all the numbers together, and all the variables
-56x^2+128x+24=0
a = -56; b = 128; c = +24;
Δ = b2-4ac
Δ = 1282-4·(-56)·24
Δ = 21760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{21760}=\sqrt{256*85}=\sqrt{256}*\sqrt{85}=16\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-16\sqrt{85}}{2*-56}=\frac{-128-16\sqrt{85}}{-112} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+16\sqrt{85}}{2*-56}=\frac{-128+16\sqrt{85}}{-112} $

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