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11(x-3)=5(x-11)
We move all terms to the left:
11(x-3)-(5(x-11))=0
We multiply parentheses
11x-(5(x-11))-33=0
We calculate terms in parentheses: -(5(x-11)), so:We get rid of parentheses
5(x-11)
We multiply parentheses
5x-55
Back to the equation:
-(5x-55)
11x-5x+55-33=0
We add all the numbers together, and all the variables
6x+22=0
We move all terms containing x to the left, all other terms to the right
6x=-22
x=-22/6
x=-3+2/3
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