3(3z-2)-3(4-4z)=6

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Solution for 3(3z-2)-3(4-4z)=6 equation:



3(3z-2)-3(4-4z)=6
We move all terms to the left:
3(3z-2)-3(4-4z)-(6)=0
We add all the numbers together, and all the variables
3(3z-2)-3(-4z+4)-6=0
We multiply parentheses
9z+12z-6-12-6=0
We add all the numbers together, and all the variables
21z-24=0
We move all terms containing z to the left, all other terms to the right
21z=24
z=24/21
z=1+1/7

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