3(1-2v)=-3(v-1)-v

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Solution for 3(1-2v)=-3(v-1)-v equation: 



3(1-2v)=-3(v-1)-v

We move all terms to the left:

3(1-2v)-(-3(v-1)-v)=0

We add all the numbers together, and all the variables

3(-2v+1)-(-3(v-1)-v)=0

We multiply parentheses

-6v-(-3(v-1)-v)+3=0



We calculate terms in parentheses: -(-3(v-1)-v), so:

-3(v-1)-v

We add all the numbers together, and all the variables

-1v-3(v-1)

We multiply parentheses

-1v-3v+3

We add all the numbers together, and all the variables

-4v+3

Back to the equation:

-(-4v+3)



We get rid of parentheses

-6v+4v-3+3=0

We add all the numbers together, and all the variables

-2v=0

v=0/-2

v=0

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