11(v-4)+3=2(2v+10)+16

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Solution for 11(v-4)+3=2(2v+10)+16 equation: 



11(v-4)+3=2(2v+10)+16

We move all terms to the left:

11(v-4)+3-(2(2v+10)+16)=0

We multiply parentheses

11v-(2(2v+10)+16)-44+3=0



We calculate terms in parentheses: -(2(2v+10)+16), so:

2(2v+10)+16

We multiply parentheses

4v+20+16

We add all the numbers together, and all the variables

4v+36

Back to the equation:

-(4v+36)



We add all the numbers together, and all the variables

11v-(4v+36)-41=0

We get rid of parentheses

11v-4v-36-41=0

We add all the numbers together, and all the variables

7v-77=0

We move all terms containing v to the left, all other terms to the right

7v=77

v=77/7

v=11

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