4(n-1)+2=n-1

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Solution for 4(n-1)+2=n-1 equation: 



4(n-1)+2=n-1

We move all terms to the left:

4(n-1)+2-(n-1)=0

We multiply parentheses

4n-(n-1)-4+2=0

We get rid of parentheses

4n-n+1-4+2=0

We add all the numbers together, and all the variables

3n-1=0

We move all terms containing n to the left, all other terms to the right

3n=1

n=1/3

n=1/3

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