-2(y+1)=8y-4+3(2y+2)

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Solution for -2(y+1)=8y-4+3(2y+2) equation: 



-2(y+1)=8y-4+3(2y+2)

We move all terms to the left:

-2(y+1)-(8y-4+3(2y+2))=0

We multiply parentheses

-2y-(8y-4+3(2y+2))-2=0



We calculate terms in parentheses: -(8y-4+3(2y+2)), so:

8y-4+3(2y+2)

determiningTheFunctionDomain
8y+3(2y+2)-4

We multiply parentheses

8y+6y+6-4

We add all the numbers together, and all the variables

14y+2

Back to the equation:

-(14y+2)



We get rid of parentheses

-2y-14y-2-2=0

We add all the numbers together, and all the variables

-16y-4=0

We move all terms containing y to the left, all other terms to the right

-16y=4

y=4/-16

y=-1/4

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