11(3-3b)=11(b+11)

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Solution for 11(3-3b)=11(b+11) equation: 



11(3-3b)=11(b+11)

We move all terms to the left:

11(3-3b)-(11(b+11))=0

We add all the numbers together, and all the variables

11(-3b+3)-(11(b+11))=0

We multiply parentheses

-33b-(11(b+11))+33=0



We calculate terms in parentheses: -(11(b+11)), so:

11(b+11)

We multiply parentheses

11b+121

Back to the equation:

-(11b+121)



We get rid of parentheses

-33b-11b-121+33=0

We add all the numbers together, and all the variables

-44b-88=0

We move all terms containing b to the left, all other terms to the right

-44b=88

b=88/-44

b=-2

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