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-6=1/5y-y-1
We move all terms to the left:
-6-(1/5y-y-1)=0
Domain of the equation: 5y-y-1)!=0We add all the numbers together, and all the variables
y∈R
-(-1y+1/5y-1)-6=0
We get rid of parentheses
1y-1/5y+1-6=0
We multiply all the terms by the denominator
1y*5y+1*5y-6*5y-1=0
Wy multiply elements
5y^2+5y-30y-1=0
We add all the numbers together, and all the variables
5y^2-25y-1=0
a = 5; b = -25; c = -1;
Δ = b2-4ac
Δ = -252-4·5·(-1)
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{645}}{2*5}=\frac{25-\sqrt{645}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{645}}{2*5}=\frac{25+\sqrt{645}}{10} $
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