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3(2x+4)+6(5x+6)+5=36x+53
We move all terms to the left:
3(2x+4)+6(5x+6)+5-(36x+53)=0
We multiply parentheses
6x+30x-(36x+53)+12+36+5=0
We get rid of parentheses
6x+30x-36x-53+12+36+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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