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10x=-12-3(4-10/3x)
We move all terms to the left:
10x-(-12-3(4-10/3x))=0
Domain of the equation: 3x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10x-(-12-3(-10/3x+4))=0
We multiply all the terms by the denominator
10x*3x-10+4))-(-12-3(=0
We add all the numbers together, and all the variables
10x*3x=0
Wy multiply elements
30x^2=0
a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{60}=0$
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