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10x^2=22
We move all terms to the left:
10x^2-(22)=0
a = 10; b = 0; c = -22;
Δ = b2-4ac
Δ = 02-4·10·(-22)
Δ = 880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{880}=\sqrt{16*55}=\sqrt{16}*\sqrt{55}=4\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{55}}{2*10}=\frac{0-4\sqrt{55}}{20} =-\frac{4\sqrt{55}}{20} =-\frac{\sqrt{55}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{55}}{2*10}=\frac{0+4\sqrt{55}}{20} =\frac{4\sqrt{55}}{20} =\frac{\sqrt{55}}{5} $
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