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10x-(x-12)=2x-(1+x)
We move all terms to the left:
10x-(x-12)-(2x-(1+x))=0
We add all the numbers together, and all the variables
10x-(x-12)-(2x-(x+1))=0
We get rid of parentheses
10x-x-(2x-(x+1))+12=0
We calculate terms in parentheses: -(2x-(x+1)), so:We add all the numbers together, and all the variables
2x-(x+1)
We get rid of parentheses
2x-x-1
We add all the numbers together, and all the variables
x-1
Back to the equation:
-(x-1)
9x-(x-1)+12=0
We get rid of parentheses
9x-x+1+12=0
We add all the numbers together, and all the variables
8x+13=0
We move all terms containing x to the left, all other terms to the right
8x=-13
x=-13/8
x=-1+5/8
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