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10x-(x-12)=2x-(5+x)
We move all terms to the left:
10x-(x-12)-(2x-(5+x))=0
We add all the numbers together, and all the variables
10x-(x-12)-(2x-(x+5))=0
We get rid of parentheses
10x-x-(2x-(x+5))+12=0
We calculate terms in parentheses: -(2x-(x+5)), so:We add all the numbers together, and all the variables
2x-(x+5)
We get rid of parentheses
2x-x-5
We add all the numbers together, and all the variables
x-5
Back to the equation:
-(x-5)
9x-(x-5)+12=0
We get rid of parentheses
9x-x+5+12=0
We add all the numbers together, and all the variables
8x+17=0
We move all terms containing x to the left, all other terms to the right
8x=-17
x=-17/8
x=-2+1/8
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