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10x-(x-12)=2x-(10+x)
We move all terms to the left:
10x-(x-12)-(2x-(10+x))=0
We add all the numbers together, and all the variables
10x-(x-12)-(2x-(x+10))=0
We get rid of parentheses
10x-x-(2x-(x+10))+12=0
We calculate terms in parentheses: -(2x-(x+10)), so:We add all the numbers together, and all the variables
2x-(x+10)
We get rid of parentheses
2x-x-10
We add all the numbers together, and all the variables
x-10
Back to the equation:
-(x-10)
9x-(x-10)+12=0
We get rid of parentheses
9x-x+10+12=0
We add all the numbers together, and all the variables
8x+22=0
We move all terms containing x to the left, all other terms to the right
8x=-22
x=-22/8
x=-2+3/4
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