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10x+5(5x-3)=5(6x+4)
We move all terms to the left:
10x+5(5x-3)-(5(6x+4))=0
We multiply parentheses
10x+25x-(5(6x+4))-15=0
We calculate terms in parentheses: -(5(6x+4)), so:We add all the numbers together, and all the variables
5(6x+4)
We multiply parentheses
30x+20
Back to the equation:
-(30x+20)
35x-(30x+20)-15=0
We get rid of parentheses
35x-30x-20-15=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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