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1/5(5x-30)=-2/3(2x-18)
We move all terms to the left:
1/5(5x-30)-(-2/3(2x-18))=0
Domain of the equation: 5(5x-30)!=0
x∈R
Domain of the equation: 3(2x-18))!=0We calculate fractions
x∈R
(3x2/(5(5x-30)*3(2x-18)))+(-(-10x5)/(5(5x-30)*3(2x-18)))=0
We calculate terms in parentheses: +(3x2/(5(5x-30)*3(2x-18))), so:
3x2/(5(5x-30)*3(2x-18))
We multiply all the terms by the denominator
3x2
We add all the numbers together, and all the variables
3x^2
Back to the equation:
+(3x^2)
We calculate terms in parentheses: +(-(-10x5)/(5(5x-30)*3(2x-18))), so:
-(-10x5)/(5(5x-30)*3(2x-18))
We add all the numbers together, and all the variables
-(-10x^5)/(5(5x-30)*3(2x-18))
We multiply all the terms by the denominator
-(-10x^5)
We do not support expression: x^5
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