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10x+4=3(2x-3)+4(x+2)
We move all terms to the left:
10x+4-(3(2x-3)+4(x+2))=0
We calculate terms in parentheses: -(3(2x-3)+4(x+2)), so:We get rid of parentheses
3(2x-3)+4(x+2)
We multiply parentheses
6x+4x-9+8
We add all the numbers together, and all the variables
10x-1
Back to the equation:
-(10x-1)
10x-10x+1+4=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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