z+32=56-z

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Solution for z+32=56-z equation: 



z+32=56-z

We move all terms to the left:

z+32-(56-z)=0

We add all the numbers together, and all the variables

z-(-1z+56)+32=0

We get rid of parentheses

z+1z-56+32=0

We add all the numbers together, and all the variables

2z-24=0

We move all terms containing z to the left, all other terms to the right

2z=24

z=24/2

z=12

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