20z-56=17z-29

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Solution for 20z-56=17z-29 equation: 



20z-56=17z-29

We move all terms to the left:

20z-56-(17z-29)=0

We get rid of parentheses

20z-17z+29-56=0

We add all the numbers together, and all the variables

3z-27=0

We move all terms containing z to the left, all other terms to the right

3z=27

z=27/3

z=9

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