10x(3x-1)=4(5x-10)

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Solution for 10x(3x-1)=4(5x-10) equation: 



10x(3x-1)=4(5x-10)

We move all terms to the left:

10x(3x-1)-(4(5x-10))=0

We multiply parentheses

30x^2-10x-(4(5x-10))=0



We calculate terms in parentheses: -(4(5x-10)), so:

4(5x-10)

We multiply parentheses

20x-40

Back to the equation:

-(20x-40)



We get rid of parentheses

30x^2-10x-20x+40=0

We add all the numbers together, and all the variables

30x^2-30x+40=0

a = 30; b = -30; c = +40;
Δ = b2-4ac
Δ = -302-4·30·40
Δ = -3900
Delta is less than zero, so there is no solution for the equation

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