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p=4/p+9=
We move all terms to the left:
p-(4/p+9)=0
Domain of the equation: p+9)!=0We get rid of parentheses
p∈R
p-4/p-9=0
We multiply all the terms by the denominator
p*p-9*p-4=0
We add all the numbers together, and all the variables
-9p+p*p-4=0
Wy multiply elements
p^2-9p-4=0
a = 1; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·1·(-4)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{97}}{2*1}=\frac{9-\sqrt{97}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{97}}{2*1}=\frac{9+\sqrt{97}}{2} $
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