10x(1/2x)(4)=40

Solution for 10x(1/2x)(4)=40 equation:

10x(1/2x)(4)=40

We move all terms to the left:

10x(1/2x)(4)-(40)=0


Domain of the equation: 2x)4!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

10x(+1/2x)4-40=0

We multiply parentheses

40x^2-40=0

a = 40; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·40·(-40)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*40}=\frac{-80}{80}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*40}=\frac{80}{80}
=1
$