6(1+7a)=40+8a

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Solution for 6(1+7a)=40+8a equation: 



6(1+7a)=40+8a

We move all terms to the left:

6(1+7a)-(40+8a)=0

We add all the numbers together, and all the variables

6(7a+1)-(8a+40)=0

We multiply parentheses

42a-(8a+40)+6=0

We get rid of parentheses

42a-8a-40+6=0

We add all the numbers together, and all the variables

34a-34=0

We move all terms containing a to the left, all other terms to the right

34a=34

a=34/34

a=1

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