8(b+3)-8=2(2b-2)

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Solution for 8(b+3)-8=2(2b-2) equation: 



8(b+3)-8=2(2b-2)

We move all terms to the left:

8(b+3)-8-(2(2b-2))=0

We multiply parentheses

8b-(2(2b-2))+24-8=0



We calculate terms in parentheses: -(2(2b-2)), so:

2(2b-2)

We multiply parentheses

4b-4

Back to the equation:

-(4b-4)



We add all the numbers together, and all the variables

8b-(4b-4)+16=0

We get rid of parentheses

8b-4b+4+16=0

We add all the numbers together, and all the variables

4b+20=0

We move all terms containing b to the left, all other terms to the right

4b=-20

b=-20/4

b=-5

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