10b-45=3(1b-45)

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Solution for 10b-45=3(1b-45) equation: 



10b-45=3(1b-45)

We move all terms to the left:

10b-45-(3(1b-45))=0

We add all the numbers together, and all the variables

10b-(3(b-45))-45=0



We calculate terms in parentheses: -(3(b-45)), so:

3(b-45)

We multiply parentheses

3b-135

Back to the equation:

-(3b-135)



We get rid of parentheses

10b-3b+135-45=0

We add all the numbers together, and all the variables

7b+90=0

We move all terms containing b to the left, all other terms to the right

7b=-90

b=-90/7

b=-12+6/7

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