12-7(n-4)+n=2

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Solution for 12-7(n-4)+n=2 equation: 



12-7(n-4)+n=2

We move all terms to the left:

12-7(n-4)+n-(2)=0

We add all the numbers together, and all the variables

n-7(n-4)+10=0

We multiply parentheses

n-7n+28+10=0

We add all the numbers together, and all the variables

-6n+38=0

We move all terms containing n to the left, all other terms to the right

-6n=-38

n=-38/-6

n=6+1/3

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