-4-(8x-4)=4(5-x)-12

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Solution for -4-(8x-4)=4(5-x)-12 equation: 



-4-(8x-4)=4(5-x)-12

We move all terms to the left:

-4-(8x-4)-(4(5-x)-12)=0

We add all the numbers together, and all the variables

-(8x-4)-(4(-1x+5)-12)-4=0

We get rid of parentheses

-8x-(4(-1x+5)-12)+4-4=0



We calculate terms in parentheses: -(4(-1x+5)-12), so:

4(-1x+5)-12

We multiply parentheses

-4x+20-12

We add all the numbers together, and all the variables

-4x+8

Back to the equation:

-(-4x+8)



We add all the numbers together, and all the variables

-8x-(-4x+8)=0

We get rid of parentheses

-8x+4x-8=0

We add all the numbers together, and all the variables

-4x-8=0

We move all terms containing x to the left, all other terms to the right

-4x=8

x=8/-4

x=-2

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