10a-3=2(4a+510a)

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Solution for 10a-3=2(4a+510a) equation: 



10a-3=2(4a+510a)

We move all terms to the left:

10a-3-(2(4a+510a))=0

We add all the numbers together, and all the variables

10a-(2(+514a))-3=0



We calculate terms in parentheses: -(2(+514a)), so:

2(+514a)

We multiply parentheses

1028a

Back to the equation:

-(1028a)



We add all the numbers together, and all the variables

-1018a-3=0

We move all terms containing a to the left, all other terms to the right

-1018a=3

a=3/-1018

a=-3/1018

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