(3m+2)=(m-1)

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Solution for (3m+2)=(m-1) equation: 



(3m+2)=(m-1)

We move all terms to the left:

(3m+2)-((m-1))=0

We get rid of parentheses

3m-((m-1))+2=0



We calculate terms in parentheses: -((m-1)), so:

(m-1)

We get rid of parentheses

m-1

Back to the equation:

-(m-1)



We get rid of parentheses

3m-m+1+2=0

We add all the numbers together, and all the variables

2m+3=0

We move all terms containing m to the left, all other terms to the right

2m=-3

m=-3/2

m=-1+1/2

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