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4/7x=3x
We move all terms to the left:
4/7x-(3x)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
-3x+4/7x=0
We multiply all the terms by the denominator
-3x*7x+4=0
Wy multiply elements
-21x^2+4=0
a = -21; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-21)·4
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{21}}{2*-21}=\frac{0-4\sqrt{21}}{-42} =-\frac{4\sqrt{21}}{-42} =-\frac{2\sqrt{21}}{-21} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{21}}{2*-21}=\frac{0+4\sqrt{21}}{-42} =\frac{4\sqrt{21}}{-42} =\frac{2\sqrt{21}}{-21} $
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